silverpie
Joined: Aug 17, 2014
|
  Posted:
Aug 31, 2014 - 02:16 |
|
mikere wrote: | The odds aren't really that hard to calculate. If you have a 12 man team the chance of a particular player getting mvp x times in y games is (1/12^x)* (11/12^y-x) * y!/(y-x)! if I'm not mistaken. |
Almost right. Add an x! to the denominator and it's there. That, and it needs different parentheses:
(1/12)^x * (11/12)^(y-x) / {y!/[x!*(y-x)!]} |
|
|
mikere
Joined: Apr 08, 2010
|
  Posted:
Aug 31, 2014 - 20:58 |
|
And that's what I get for just working it out before coffee and not looking up the combinations formula! Thanks for the correction. |
|
|
PaddyMick
Joined: Jan 03, 2012
|
  Posted:
Aug 31, 2014 - 21:10 |
|
The chance of anything happening ever to anyone anywhere is 50/50 |
|
|
pythrr
Joined: Mar 07, 2006
|
  Posted:
Aug 31, 2014 - 21:26 |
|
PaddyMick wrote: | The chance of anything happening ever to anyone anywhere is 50/50 |
Unless it is a million to one chance. Then it is must always succeed due to narrative logic. |
_________________
|
|
silverpie
Joined: Aug 17, 2014
|
  Posted:
Sep 02, 2014 - 00:06 |
|
Or due to the use of an Infinite Improbability Drive... hmm, is there a way to make a Secret Weapon out of that? |
|
|